Q6) Which of the following methods allows us to call generic methods as a normal method? Answer: c Clarification: A generic type, such as a gene, is an abstraction. In C# terminology, a construct such as Gene is called an open constructed type because it specifies the T-type parameter (not an actual type such as int). Part of the generic Java quiz – 1 | In Java Generics, the feature was introduced in the Java 5 release to dynamically provide the type of the parameter and return type of the method by performing a compile-time type check to resolve ClassCastException. Here we see various Java Generics test questions. Q1) What are the advantages of generic Java? Q3) Which of these types cannot be used to initiate a generic type? 2. Which of these type parameters is used for generic methods to return and accept any object type? a) K b) N c) T d) V a) Type Interfaceb) Interfacec) Internal classd) All mentioned See answer Answer:- a) Type InterfaceType inference, allows us to call a generic method as an ordinary method without specifying a type in square brackets. Q9) If we declare ArrayList to be String, what kind of items can we add to ArrayList? Can you find the options that are not valid? (More than options are not valid) Q11) Which of the following object creation methods is not valid for the following test class? 3. Which of these definitions is correct from the generic method? (a) name(T1, T2, …, Tn) { /* . */ } b) public name { /* . */ } c) class name[T1, T2, …, Tn] { /* . */ } d) name{T1, T2, …, Tn} { /* . */ } Java Generics Quiz – Java Generics Multiple Choice Q&A: Use this article and take the Java Generics Quiz.

If you try the Java Generics Online Quiz test that you can find on this page, you will learn what kind of questions were asked in the technical interviews. Once you submit the Java Generics MCQ quiz, you can learn more about the Java Generics Multiple Choice questions and answers that appear on the screen. Try the Java Generics Online test now and get ready for Java Generics concepts in areas where you are lagging behind. Q14) We can define related types in combination. Which of the following statements is valid? Answer: d Precision: Gen Class Defines the generic declaration, where `T` is the name of the type parameter. This parameter is used as a placeholder for the actual type specified when creating a Gen object. Gene is a generic class. T is used to declare a variable called `if`. To participate in such a Java Generics Online test, be sure to follow us @ freshersnow.com. a) Test t1 = new Test();b) Test t2 = new Test() ;c) Test t3 = new Test();d) None of these answers: d) None of themThis question is similar to the previous question. We can pass the Runnable type or its implementation class.

Option (a) is valid because we pass the Runnable interface. The MyThread1 class extends the Thread class, and the Thread class implements the Runnable interface, so the MyThread1 class is also indirectly an implementation class of the Runnable interface. Therefore, option (b) is valid. The MyThread2 class implements the Runnable interface, so option (c) is also valid. a) Test { }b) Test { }c) Test { }d) All these See Answer Answer:- a) Test { }According to OOP, the class must first be taken before the interface name. But in option (b) we used “extended Runnable & Number”, the correct form is: – “extended Number & Runnable”. Normally, “Class A extended B implements C” is valid, but “Class A implements C extended B” is not valid because the class must be taken first relative to the interface. Therefore, option (b) is not valid. In option (c), Number and Thread are classes. According to OOP, each Java class cannot extend more than one class at a time. Therefore, option (c) is also not valid.

a) Test t1 = new Test();b) Test t2 = new Test() ;c) Test t3 = new Test();d) None of these 9. Are you choosing the correct way to call the fun() subroutine of the example class? In this article, we have provided multiple-choice questions on Java arrays to test your knowledge of arrays in Java. a) Test { }b) Test { }c) super Runnable Test { }d) All this a) Generic class decleration b) Variable decleration c) Generic manufacturer decleration d) All that is mentioned a) Generic class declaration b) Declaration of the variable c) A simple class declaration d) Generic class declaration and variable declaration Q10) Which of these elements is a valid declaration of a class? a) Compilation error b) Csharp c) 0 d) Runtime error 8. Do you select the type argument of the open constructed type? a) Gen b) Gen c) Gen d) None of the above. a) Anonymous internal classb) Interfacec) Internal class) All mentioned a) Test { }b) Test { }c) Class Test { }d) Class Test { }Show response Answer:- c) Class Test { }The syntax for defining bounded types in combination is:- Class test , we can`t use implementations or super keywords. a) ArrayList al1 = new ArrayList();b) ArrayList al2 = new ArrayList();c) ArrayList al3 = new ArrayList( );d) ArrayList al4 = new ArrayList(); Show response Answer:- b) ArrayList al2 = new ArrayList(); For the type parameter, we can specify any class/interface name, but not a primitive name. When we try to deploy primitives, we get a compilation error. We recommend that you try these code snippets in the Eclipse IDE and understand how the program works (but the answer with the explanation at the end of each question). These questions may be asked in interviews or similar questions may appear in interviews, so be prepared. (a) test t1 = new test();b) test t2 = new test();c) test t3 = new test( );d) test t4 = new test(); Show response Answer:- b) Test t2 = new Test();D the syntax “class Test { }”, if the X is a class, we can pass either type X or its child class type. The linked test type is “Number”, so we can pass the “Number” type or its child class.

Integer and Double are child classes of Number. But the “Number” and “String” classes are sisters, so we can`t pass String. See also:- Java Generics Quiz Part – 2, Java Generics Quiz Part – 3. Home » Technical Quiz » Java Generics Quiz – Java Generics Multiple Choice Questions and Answers. a) Generics make code fasterb) Generics make code more optimized and readablec) Generics add stability to your code by revealing more of your errors at compile time) Generics add stability to your code by revealing more of your errors at run time. a) ArrayList al1 = new ArrayList();b) List al2 = new ArrayList();c) Collection al3 = new ArrayList( );d) ArrayList al4 = new ArrayList(); Show answer:- d) ArrayList al4 = new ArrayList(); The polymorphism applies only to the base type, not the parameter type. For object (d), we get a compilation error:- incompatible types: ArrayList cannot be converted to ArrayList a) al.add(“KnowProgram”);b) al.add(null);c) al.add( 10);d) al.add(new StringBuilder(“Generic”)); Show answer Answer: (c) and (d) are not valid. If we declare ArrayList of type String, we can only add elements of type String to ArrayList. When we try to add another type, we get a compilation error. Here, (a) is valid because “KnowProgram” is of type String, (b) is also valid because zero is the default value for all objects, (c) is not valid because 10 is of type integer, (d) is also invalid because “Generic” is a StringBuilder type and we cannot add it to ArrayList of type String.

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